Question

POR FAVOR URGENTE !!!!​

Answer 1

1)

$\frac{3}{4} + \frac{5}{8} - \frac{1}{2} = \\ \frac{(8 \times 3) + (4 \times 5)}{4 \times8 } - \frac{1}{2} = \\ \frac{24 + 20}{32} - \frac{1}{2} = \\ \frac{44}{32 } - \frac{1}{2} = \\ \frac{(44 \times 2 )- (32 \times 1)}{32 \times 2} = \\ \frac{88 - 32}{64} = \\ \frac{56}{64} = \\ \frac{56 \div 8}{64 \div 8} = \\ \frac{7}{8}$

2)

$\frac{10}{7} - \frac{1}{2} + \frac{1}{14} = \\ \frac{(10 \times 2 )- (7 \times 1)}{7 \times 2} + \frac{1}{14} = \\ \frac{20 - 7}{14} + \frac{1}{14} = \\ \frac{13}{14 } + \frac{1}{14} = \\ \frac{13 + 1}{14} = \\ \frac{14}{14} = \\ 1$

3)

$\frac{8}{3} - \frac{1}{2} + \frac{10}{6} = \\ \frac{(8 \times 2) - (3 \times 1)}{3 \times 2} + \frac{10}{6} = \\ \frac{16 - 3}{6} + \frac{10}{6} = \\ \frac{13}{6} + \frac{10}{6} = \\ \frac{13 + 10}{6} = \\ \frac{23}{6}$

Também há uma segunda forma de resolver que é através do m.m.c. dos denominadores:

1)

$\frac{3}{4} + \frac{5}{8} - \frac{1}{2} = \\ \frac{((8 \div 4) \times 3) + ((8 \div 8) \times 5) - ((8 \div 2) \times 1}{8} = \\ \frac{6 + 5 -4 }{8} = \\ \frac{7}{8}$

2)

$\frac{10}{7} - \frac{1}{2} + \frac{1}{14} = \\ \frac{((14 \div 7) \times 10) - ((14 \div 2) \times 1) + ((14 \div 14) \times 1)}{14} = \\ \frac{20 - 7 + 1}{14} = \\ \frac{14}{14} = \\ 1$

3)

$\frac{8}{3} - \frac{1}{2} + \frac{10}{6} = \\ \frac{((6 \div 3) \times 8) - ((6 \div 2) \times 1) + ((6 \div 6) \times 10)}{6} = \\ \frac{16 - 3 + 10}{6} = \\ \frac{23}{6}$

Espero ter ajudado!