Question

por favor resolvam pra mim seria de grande ajuda ,se puder ponha conta

Answer 1

$a) \ \frac{6}{\sqrt6-\sqrt2}*\frac{\sqrt6+\sqrt2}{\sqrt6+\sqrt2}=\frac{6(\sqrt6+\sqrt2)}{4}\\ \\ b) \ \frac{\sqrt2-\sqrt3}{\sqrt2+\sqrt3}.\frac{\sqrt2-\sqrt3}{\sqrt2-\sqrt3}=\frac{5-2\sqrt6}{-1}=2\sqrt6-5\\ \\ c) \ \frac{2}{ \sqrt[5]{4} }.\frac{ \sqrt[5]{4^4} }{\sqrt[5]{4^4}}=\frac{2\sqrt[5]{4^4}}{4}=\frac{\sqrt[5]{4^4}}{2}\\ \\ d) \ \frac{3}{8 \sqrt[4]{2^3} }.\frac{ \sqrt[4]{2} }{ \sqrt[4]{2} }=\frac{3 \sqrt[4]{2} }{8.2}=\frac{3 \sqrt[4]{2} }{16}$

$e) \ \frac{12}{3+\sqrt5}.\frac{3-\sqrt5}{3-\sqrt5}=\frac{12(3-\sqrt5)}{9-5}=\frac{12(3-\sqrt5)}{4}=3(3-\sqrt5)$