Question

por favor resolvam!!

h)x/2+3x/4=10-5x/8
i)13-y/8=3y/4-1
j)x/2-1/3=x/4
k)1/2-3.(1+1)/4=-1/3​

Answer 1

h)

$\dfrac{x}{2}+\dfrac{3x}{4}=10-\dfrac{5x}{8}\times(8)\\4x+6x=80-5x$

$10x+5x=80\\15x=80\\x=\dfrac{80}{15}$

$\bf{x=\dfrac{16}{3}}$

i)

$13-\dfrac{y}{8}=\dfrac{3y}{4}-1</p><p>\times(8)\\104-y=6y-8\\6y+y=104+8$

$7y=112\\y=\dfrac{112}{7}$

$\bf{y=16}$

j)

$\dfrac{x}{2}-\dfrac{1}{3}=\dfrac{x}{4}\times12$

$</p><p>6x-4=3x\\6x-3x=4\\3x=4$

$\bf{x=\dfrac{4}{3}}$

k) não é equação embora seja uma igualdade.