Matemática, perguntado por rehydudu02, 11 meses atrás

Por favor, quem puder resolver.​

Anexos:

Soluções para a tarefa

Respondido por luanafbh2
1

a) A + B

\left[\begin{array}{ccc}2&3&4\\5&1&6\end{array}\right] + \left[\begin{array}{ccc}-2&1&0\\3&-5&7\end{array}\right] = \left[\begin{array}{ccc}2-2&3+1&4+0\\5+3&1-5&6+7 \end{array}\right] = \left[\begin{array}{ccc}0&4&4\\8&-4&13\end{array}\right]

b) B - A

\left[\begin{array}{ccc}-2&1&0\\3&-5&7\end{array}\right]  - \left[\begin{array}{ccc}2&3&4\\5&1&6\end{array}\right] = \left[\begin{array}{ccc}-2-2&1-3&0-4\\3-5&-5-1&7-6\end{array}\right] = \left[\begin{array}{ccc}0&-2&-4\\-2&-6&1\end{array}\right]

c) (A - B)T

\left[\begin{array}{ccc}2&3&4\\5&1&6\end{array}\right] - \left[\begin{array}{ccc}-2&1&0\\3&-5&7\end{array}\right] = \left[\begin{array}{ccc}2+2&3-1&4-0\\5-3&1+5&6-7 \end{array}\right] = \left[\begin{array}{ccc}4&2&4\\-2&6&-1\end{array}\right]

\left[\begin{array}{ccc}4&2&4\\-2&6&-1\end{array}\right]^t = \left[\begin{array}{ccc}4&-2\\2&6\\4&-1\end{array}\right]

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