Question

Por favor, podem me ajudar?

[3^(x+2)*9^x]/243^(5x+1)=[(81^2x)]/27^(3-4x)

Answer 1

 ((3^X+2) * (9^X) /243 ^(5X+1) = ((81^2X ) / ((27^(3-4X )) 
[ ( 3^( X+2 ) x ( 3^2) ^X ) / ( ( 3^5 ^(5X+1 ) ] = ((3^4^(2X ) / 3 ^3( 3-4X)) 
3^x+2 X 3^2x/ 3^25x+5 = 3^8x / 3^ 9 -12x 

X+2 + 2x - 25x - 5 = 8x -9 +12x 

-22x -3 = 20x - 9 

-42x = -6 
x = 7