Question

por favor mim ajude a achar essa resposta

Answer 1

$Ola'~~~\mathbb{SAMARA} \\ \\ A~condic\~ao~indica~que: \\ \\ A= B^{t} ~~---\ \textgreater \ substituindo~temos: \\ \\ \begin{bmatrix} 2^{a+1} &log( \frac{1}{100}) \\ \\ 3^{-2}&5 \end{bmatrix}=\begin{bmatrix} \frac{1}{8}&c \\ \\ b&5 \end{bmatrix}~~, por~igualac\~ao \\ \\ \\ 2^{a+1= \frac{1}{8} } \\ 2^{a+1}= 2^{-3}~~,bases~iguais, expoente~se~iguala \\ a+1=-3 \\ \boxed{a=-4 } \\ \\ ============================== \\ log (\frac{1}{100})=c \\ log 10^{-2} =c \\ -2\underbrace{log10}_{1}=c$

$\boxed{c=-2} \\ \\ ============================== \\ 3^{-2}=b \\ \boxed{b= \frac{1}{9} } \\ \\ ============================== \\ Respondendo~a pergunta~temos~: \\ Afirmar~que~a+3b-c~~ e'~igual~a:, substituindo~valores~temos: \\ \\ a+3b-c=-4+3( \frac{1}{9})-(-2) \\ \\ \boxed{\boxed{a+3b-c=- \frac{5}{3} }} \\ \\ \\ \mathbb{iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii} \\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Espero~ter~ajudado!!$