Question

por favor me ajudem...
qual é o valor de:(a+b)²-(a-b)²+2a·(a+3)-4·(6ab+3)=

Answer 1

(a+b)²-(a-b)²+2a·(a+3)-4·(6ab+3) =

a²+2ab+b²-(a²-2ab+b²)+2a²+6a-24ab-12 =

a²+2ab+b²-a²+2ab-b²+2a²+6a-24ab-12 =

a²-a²+2a²+b²-b²+2ab+2ab-24ab+6a-12 =

2a²-20ab+6a-12

Answer 2

Boa tarde

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

2a*(a + 3) = 2a² + 6a

4*(6ab + 3) = 24ab - 12

a² + 2ab + b² - (a² - 2ab + b²) = 4ab

4ab + 2a² + 6a - 24ab - 12 = 2a² - 20ab + 6a - 12