Question

Por favor me ajudem preciso urgentemente!
B)√0,111...-√0,09
C)1-1/√9+0,666...

Answer 1

$Ola! \\ \\ \boxed{a} \\ \\ \sqrt{0,1111......} - \sqrt{0,09} ~~~--\ \textgreater \ \begin{cases}0,11111......= \frac{1}{9} \\ \\ 0,09= \frac{9}{100} \end{cases} \\ \\ Substituimos: \\ \\ \sqrt{ \frac{1}{9} } - \sqrt{ \frac{9}{100} } \\ \\ \frac{1}{3}- \frac{3}{10} ~~--\ \textgreater \ m.m.c=30 \\ \\ \frac{30-9}{30} = \frac{21}{30}= \boxed{\boxed{\frac{7}{10}~~ou~~ 0,7}}$
$======================================= \\ \boxed{b} \\ \\ 1- \frac{1}{ \sqrt{9}}+0,666...~~~~--\ \textgreater \ \big\{0,666...= \frac{6}{9}= \boxed{\frac{2}{3}} \\ \\ =\ \textgreater \ 1- \frac{1}{ \sqrt{9 } } + \frac{2}{3} \\ \\ =\ \textgreater \ 1- \frac{1}{ 3 } }+ \frac{2}{3} \\ \\ \frac{3-1+2}{3} = \boxed{\boxed{\frac{4}{3}~~ou~~1,33333....}} \\ \\ \\ Bons~estudos!$