Question

por favor me ajudem nessa!
Se A + (6^2 . 9^5)^-4
Obrigada!!!

Answer 1

$(6^2 \cdot 9^5)^{-4}=[(2\cdot3)^2 \cdot (3^2)^5]^{-4}=[2^2\cdot3^2 \cdot 3^{2\cdot5}]^{-4}=[2^2\cdot3^2\cdot3^{10}]^{-4}\\ \\=[2^2\cdot3^{2+10}]^{-4}=[2^2\cdot3^{12}]^{-4}=2^{2\cdot{(-4)}}\cdot3^{12\cdot(-4)}=2^{-8}\cdot3^{-48}$