Question

POR FAVOR ME AJUDEM complete:

a) (a+3)²= __+2.a.3+
__=__=__+__+9

b) (a+4b)²=___+2.a.4b+(4b)²=___=___+__+16b²

c) (2x+3y)²=(2x)²+2.2x.___+___=__=__+12xy+​

Answer 1

Resposta:

${(a + 3)}^{2} = {a}^{2} + 2a \times 3 + {3}^{2} = {a }^{2} + 6a + 9$

${(a + 4b)}^{2} = {a}^{2} + 2a \times 4b + {(4b)}^{2} = {a}^{2} + 8ab + {16}^{2}$

${(2x + 3y)}^{2} = {(2x)}^{2} + 2 \times 2x \times 3y + {(3y)}^{2} = {4x}^{2} + 12 {}^{} xy + 9 {y}^{2}$