Question

por favor me ajudem!!
calcular y'
sendo y= 10x³-8x²+12x-9

Answer 1

y= 10x³ -8x²+12x-9

y'= 3.10x³-¹ -2.8x²-¹ + 12.1 -0

y'= 3.10x² -2.8x +12

y' = 30x² - 16x + 12

Answer 2

$\mathtt{y=10{x}^{3}-8{x}^{2}+12x-9}$

$\mathtt{\dfrac{dy}{dx}=3.10{x}^{3-1}-2.8{x}^{2-1}+12}$

$\huge\boxed{\boxed{\mathtt{\dfrac{dy}{dx}=30{x}^{2}-16x+12}}}$