Por Favor Me ajude PFV!!!!!!!!
Soluções para a tarefa
(2-x)²+2=(2+1)²+10
4-2x-2x+x²+2=4+2+2+1+10
4-4x+x²+2=19
x²-4x+6=19
x²-4x+6-19=0
x²-4x-13=0
delta = b²-4*a*c => (-4)²-4*1*-13 => 16-4*-13 => 16+52 => 68
x = -b±√delta => -(-4)±√68
________ _________
2*a 2
x' = -(-4)+√68 => 4+√68 => 4+8,246 = 12,246 = 6,123
_________ _______ ________ ________
2 2 2 2
ou = √17+2
x'' = -(-4)-√68 => 4-√68 => 4-8,246 = -4,246 = -2,123
_________ _______ ________ ________
2 2 2 2
ou = 2-√17