Question

Por favor!!!! me ajuda. Dada a função esponencial f(x)=25²x+¹, calcule
A) f(1)=
B f(1 sobe 2)=

Answer 1

$f(x)=25^{2x+1}\\ \\ a) \ f(1)=25^{2.1+1}=25^3=15625\\ \\ b) \ f(\frac{1}{2})=25^{2.\frac{1}{2}+1}=25^{1+1}=25^2=625$