Question

Por favor me ajuda aí,eu preciso que voce responda essas duas questões ai, preciso entregar essa atividade amanhã

Answer 1

$A= \left[\begin{array}{ccc}6&2\\4&3 \end{array}\right] = [6*3] -[ 2*4] = 18-8=10\\\\\\ B= \left[\begin{array}{ccc}-3&-8\\1&2 \end{array}\right] = [-3*2] -[-8*1] = -6+8= 2\\\\\\ C= \left[\begin{array}{ccc}1+\sqrt{5}&3\\4&1-\sqrt{5} \end{array}\right] = [(1+\sqrt{5})*(1-\sqrt{5}) ]- [4*3] =\\\\C= [1^2-(\sqrt{5})^2]-[12] = [1-5]-[12]=4-12=8\\\\\\ D=\left[\begin{array}{ccc} \frac{3}{4} & 2 \\ \frac{1}{2}&-3 \end{array}\right] = [ \frac{3}{4}*(-3)] - [2* \frac{1}{2} ] = \frac{-9}{4}- 1= \frac{-13}{4}$



2)

$a=\left[\begin{array}{ccc}1&3\\-2&5 \end{array}\right] = [1*5]-[3*(-2)] = [5]-[-6]=5+6=11\\\\\\\\ b= \left[\begin{array}{ccc}2&6\\3&10 \end{array}\right] = [2*10]-[6*3] = 20-18=2\\\\\\ c=\left[\begin{array}{ccc}2&8\\0&-1 \end{array}\right]=[2*(-1)]-[8*0]= -2-8 = -2\\\\\\\ a^2+3b-2c = 11^2+3*2-2*(-2)=121+6+4 = 131$