Question

por favor gente me ajudem !

Answer 1

a) -3x +12≥ 0

-3x ≥ -12
 3x≤12
x ≤12/3
x ≤4
D= {x ∈ R/ x  ≤  4}

b)  x-3 >0
x > 3

D= {x∈ R /x >3}

4)$\frac{-x}{2} + \frac{9}{2} =0$

-x =-9
 x=9



9x -81=0
9x=81
x = 81÷9
x =9


6) sen = 5/6

   cosa =√11/6

   tga = 5/√11 = 5√11/11

  sena/cosa= tga = 5√11/11