Question

Por favor , é para amanhã
1-) Resolva as equações.
a-) 8x-40= 6 . (x-2)
b-) 6 . (x -2) = 4+3 . (x-1)
c-) 12 . (x-3) - 6 . (x+1)= -6
d-) 4 x - (x+2) = -x+3
e-) 3x + 3 . (12-2x) = 120
f-) 4 . (2x+3) - (5x+7) = 2 . (3-4x)
g-) -(2x+6) - 4x= -2 . (x+1) -12
h-) -6 . (x+2) - 12 =2 . (x+4) - 8
i-) 3 . (x+2) + 4 . (x+3) = 8
j-) 4 . (2x+6) -3 = 2 . (x-4) +11

Answer 1

Bom dia, BeatrizPain!

a) $8x-40=6(x-2) \iff 8x-40=6x-12$

$8x-6x=40-12 \iff 2x=28$

$x=\dfrac{28}{2} \iff \boxed{x=14}$


b) $6(x-2)=4+3(x-1) \iff 6x-12=4+3x-3$

$6x-3x=1+12 \iff 3x=13$

$\boxed{x=\dfrac{13}{3}}$


c) $12(x-3)-6(x+1)=-6 \iff 12x-36-6x-6=-6$

$12x-6x=-6+6+36 \iff 6x=36$

$x=\dfrac{36}{6} \iff \boxed{x=6}$


d) $4x-(x+2)=-x+3 \iff 4x-x-2=-x+3$

$4x-x+x=3+2 \iff 4x=5$

$\boxed{x=\dfrac{5}{4}}$


e) $3x+3(12-2x)=120 \iff 3x+36-6x=120$

$3x-6x=120-36 \iff -3x=84$

$x=\dfrac{84}{-3} \iff \boxed{x=-28}$


f) $4(2x+3)-(5x+7)=2(3-4x) \iff 8x+12-5x-7=6-8x$

$8x-5x+8x=6-12+7 \iff 11x=1$

$\boxed{x=\dfrac{1}{11}}$


g) $-(2x+6)-4x=-2(x+1)-12 \iff -2x-6-4x=-2x-2-12$

$-2x-4x+2x=-2-12+6 \iff -4x=-8$

$x=\dfrac{-8}{-4} \iff \boxed{x=2}$


h) $-6(x+2)-12=2(x+4)-8 \iff -6x-12-12=2x+8-8$

$-6x-2x=8-8+12+12 \iff -8x=24$

$x=\dfrac{24}{-8} \iff \boxed{x=-3}$


i) $3(x+2)+4(x+3)=8 \iff 3x+6+4x+12=8$

$3x+4x=8-12-6 \iff 7x=-10$

$\boxed{x=\dfrac{-10}{7}}$


j) $4(2x+6)-3=2(x-4)+11 \iff 8x+24-3=2x-8+11$

$8x-2x=-8+11-24+3 \iff 6x=-18$

$x=\dfrac{-18}{6} \iff \boxed{x=-3}$