Por favor, como fatorar x^9 + y^9?
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Primeiro, recordemos o seguinte produto notável:
(Soma de cubos)

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Então, temos que
![x^9+y^9\\\\ =x^{3\,\cdot\,3}+y^{3\,\cdot\,3}\\\\ =(x^{3})^3+(y^{3})^3~~~\rightarrow~~\text{(soma de cubos)}\\\\ =(x^3+y^3)\left[(x^3)^2-x^3y^3+(y^3)^2 \right ]\\\\ =\underbrace{(x^3+y^3)}_{\text{soma de cubos}}(x^6-x^3y^3+y^6)\\\\\\ =(x+y)(x^2-xy+y^2)(x^6-x^3y^3+y^6)\\\\\\ \therefore~~\boxed{\begin{array}{c} x^9+y^9=(x+y)(x^2-xy+y^2)(x^6-x^3y^3+y^6) \end{array}} x^9+y^9\\\\ =x^{3\,\cdot\,3}+y^{3\,\cdot\,3}\\\\ =(x^{3})^3+(y^{3})^3~~~\rightarrow~~\text{(soma de cubos)}\\\\ =(x^3+y^3)\left[(x^3)^2-x^3y^3+(y^3)^2 \right ]\\\\ =\underbrace{(x^3+y^3)}_{\text{soma de cubos}}(x^6-x^3y^3+y^6)\\\\\\ =(x+y)(x^2-xy+y^2)(x^6-x^3y^3+y^6)\\\\\\ \therefore~~\boxed{\begin{array}{c} x^9+y^9=(x+y)(x^2-xy+y^2)(x^6-x^3y^3+y^6) \end{array}}](https://tex.z-dn.net/?f=x%5E9%2By%5E9%5C%5C%5C%5C+%3Dx%5E%7B3%5C%2C%5Ccdot%5C%2C3%7D%2By%5E%7B3%5C%2C%5Ccdot%5C%2C3%7D%5C%5C%5C%5C+%3D%28x%5E%7B3%7D%29%5E3%2B%28y%5E%7B3%7D%29%5E3%7E%7E%7E%5Crightarrow%7E%7E%5Ctext%7B%28soma+de+cubos%29%7D%5C%5C%5C%5C+%3D%28x%5E3%2By%5E3%29%5Cleft%5B%28x%5E3%29%5E2-x%5E3y%5E3%2B%28y%5E3%29%5E2+%5Cright+%5D%5C%5C%5C%5C+%3D%5Cunderbrace%7B%28x%5E3%2By%5E3%29%7D_%7B%5Ctext%7Bsoma+de+cubos%7D%7D%28x%5E6-x%5E3y%5E3%2By%5E6%29%5C%5C%5C%5C%5C%5C+%3D%28x%2By%29%28x%5E2-xy%2By%5E2%29%28x%5E6-x%5E3y%5E3%2By%5E6%29%5C%5C%5C%5C%5C%5C+%5Ctherefore%7E%7E%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D+x%5E9%2By%5E9%3D%28x%2By%29%28x%5E2-xy%2By%5E2%29%28x%5E6-x%5E3y%5E3%2By%5E6%29+%5Cend%7Barray%7D%7D)
(Soma de cubos)
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Então, temos que
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