Por favor coloque a conta inteira: a) (11/2´-11/4) · (2/5+1/25) b)7+(11/2-13/4·(1/2+1/2·1/5)
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a)
(11/2-11/4)*(2/5+1/25)=
(22-11/4)*(10+1/25)=
11*/4*11/25=121/100
b)
7+(11/2-13/4*(1/2+1/2*1/5)=
7+(22-13/4)*(1/2+1/10)=
7+9/4*(5+1/10)=
7+9/4*6/10=
7+54/40=
280+54/40=
324/40=81/10
(11/2-11/4)*(2/5+1/25)=
(22-11/4)*(10+1/25)=
11*/4*11/25=121/100
b)
7+(11/2-13/4*(1/2+1/2*1/5)=
7+(22-13/4)*(1/2+1/10)=
7+9/4*(5+1/10)=
7+9/4*6/10=
7+54/40=
280+54/40=
324/40=81/10
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