por favor algume pode me ajudar nessas questao que estao marcada de rosa por favor
Anexos:
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Soluções para a tarefa
Respondido por
1
6-
a) 1° termo
a1 = 7
r = 4


b)

7- a)
b)
8-
9- a1 = 1 -> 1° Número impar positivo
n = 50 -> 50° termos
r = 2

10-
a)
b)
11-

157 + 19.r = 5+0.r
157 -5 = -19.r
152 = -19.r
r = - 8
a) 1° termo
a1 = 7
r = 4
b)
7- a)
b)
8-
9- a1 = 1 -> 1° Número impar positivo
n = 50 -> 50° termos
r = 2
10-
a)
b)
11-
157 + 19.r = 5+0.r
157 -5 = -19.r
152 = -19.r
r = - 8
alicecardoso3:
porque que tem esse tex?
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