Question

Por favor alguém me ajudaaaaaaaaa

Answer 1

Resposta:

1)

1/27=3^x

3^(-3)=3^x

x=-3

Letra B

2)

3√3=√3³

log[√3³]  x =1/3

x=[√3³]^(1/3)

x=√(3^(3/3))

x=√3

Letra E

3)

A)

log 10 -log 10/5

log 10 -log 10 +log 5 = log 5

B)

log 5^(10/5)  

log 5²

2*log 5

C)

log 3+log 2= log 3*2=log 6

(B)

(C)

(A)