Por favoooooooooooooooooooooooor é pra amanha!!
Alguém pode me ajudar a resolver essas questões?
a) √(x+2)=7
b) √(3x+10)=10
c) √(x–2) –5=0
d) √(x–10)=√3x+2
e) ∛(5x–8) – ∛(3x+2)= 0
Soluções para a tarefa
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a)√x+2 =7
(√x+2)²=7²
x+2=49
x=49-2
x=47
b)√3x+10=10
(√3x+10)²=10²
3x+10=100
3x=100-10
3x=90
x=90:3
x= 30
c) √x-2) -5=0
√x-2= 5
(√x-2)²=5²
x-2=36
x=36+2
x= 38
d)√x-10= √3x+2
(√x-10)² = (√3x+2)²
x-10=3x+2
x-3x=2+10
-2x=12
x= 12: (-2)
x=-6
e)∛5x-8)- ∛3x+2)=0
(∛5x-8)³= ( ∛3x+2)³
5x-8=3x+2
5x-3x=2+8
2x=10
x=10:2
x=5
(√x+2)²=7²
x+2=49
x=49-2
x=47
b)√3x+10=10
(√3x+10)²=10²
3x+10=100
3x=100-10
3x=90
x=90:3
x= 30
c) √x-2) -5=0
√x-2= 5
(√x-2)²=5²
x-2=36
x=36+2
x= 38
d)√x-10= √3x+2
(√x-10)² = (√3x+2)²
x-10=3x+2
x-3x=2+10
-2x=12
x= 12: (-2)
x=-6
e)∛5x-8)- ∛3x+2)=0
(∛5x-8)³= ( ∛3x+2)³
5x-8=3x+2
5x-3x=2+8
2x=10
x=10:2
x=5
anvigo33:
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