Question

por favo respondam . quanto e 23-45(x-5)={3}÷5

Answer 1

$23-45\,(x-5)=\dfrac{3}{5}\\ \\ \\ -45\,(x-5)=\dfrac{3}{5}-23\\ \\ \\ -45\,(x-5)=\dfrac{3-115}{5}\\ \\ \\ -45\,(x-5)=\dfrac{-112}{5}$


Multiplicando os dois lados por $5,$

$5\cdot[-45\,(x-5)]=-112\\ \\-225\,(x-5)=-112$


Dividindo os dois lados por $-225,$

$x-5=\dfrac{-112}{-225}\\ \\ \\ x-5=\dfrac{112}{225}\\ \\ \\ x=\dfrac{112}{225}+5\\ \\ \\ x=\dfrac{112+1\,125}{225}\\ \\ \\ x=\dfrac{1\,237}{225}$