Question

Poderia me ajuadar nessa questão ∫ (t + √t + 3√t + 4√t + 5√t)dt​

Answer 1

Resposta:

∫ (t + √t + 3√t + 4√t + 5√t)  dt​

∫ t  +  13*t^(1/2)    dt​

=t²/2 + 13 * t^(3/2) /(3/2)  + constante

=t²/2 +13*2/3 *t^(3/2) + constante

=t²/2 + 26/3√t³ +constante

=t²/2 + (26/3)* t√t +constante