Question

poder me ajudar calcular matriz

Answer 1

Resposta:

$A+2B-4C= \left[\begin{array}{ccc}-6&-4&-4\\-6&4&49\end{array}\right]$

Explicação passo-a-passo:

$A=\left[\begin{array}{ccc}0&0&2\\0&-4&15\end{array}\right]$

$B=\left[\begin{array}{ccc}1&0&3\\-1&2&5\end{array}\right]$

$C=\left[\begin{array}{ccc}2&1&3\\1&-1&-6\end{array}\right]$

$A+2B-4C=$

$\left[\begin{array}{ccc}0&0&2\\0&-4&15\end{array}\right]+2\left[\begin{array}{ccc}1&0&3\\-1&2&5\end{array}\right]-4\left[\begin{array}{ccc}2&1&3\\1&-1&-6\end{array}\right]=$

$\left[\begin{array}{ccc}0&0&2\\0&-4&15\end{array}\right]+\left[\begin{array}{ccc}2\cdot1&2\cdot0&2\cdot3\\2\cdot(-1)&2\cdot2&2\cdot5\end{array}\right]-\left[\begin{array}{ccc}4\cdot2&4\cdot1&4\cdot3\\4\cdot1&4\cdot(-1)&4\cdot(-6)\end{array}\right]=$

$\left[\begin{array}{ccc}0&0&2\\0&-4&15\end{array}\right]+\left[\begin{array}{ccc}2&0&6\\-2&4&10\end{array}\right]-\left[\begin{array}{ccc}8&4&12\\4&-4&-24\end{array}\right]=$

$\left[\begin{array}{ccc}0+2-8&0+0-4&2+6-12\\0-2-4&-4+4-(-4)&15+10-(-24)\end{array}\right]=$

$\left[\begin{array}{ccc}-6&-4&-4\\-6&4&49\end{array}\right]$