Question

Podem me ajudar e o exercicio 9.1 e 9.2

Answer 1

$(\frac{1}{3}+ \frac{5}{6}): \frac{1}{6}$ ---mmc(3,6)=6

$( \frac{2+5}{6}): \frac{1}{6}=$

$\frac{7}{6}: \frac{1}{6}= \frac{7}{6}* \frac{6}{1}= \frac{42}{6}= 7$
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$\frac{1}{15}+ \frac{3}{5}: \frac{2}{5}=$

$\frac{1}{15}+ \frac{3}{5}* \frac{5}{2}=$

$\frac{1}{15}+ \frac{15}{10}=$ ---mmc(15,10) =30

$\frac{2+45}{30} = \frac{47}{30}$