Question

podem me ajudaaa? (◍•ᴗ•◍)❤​

Answer 1

Resposta:

a) $2a+2$

b) $15x-2$

c) $4x^2-8x$

d) $5y$

e) $32y-2$

f) $-1$

g) $4b^2-2b-3$

h) $-4x^2-3x+1$

i) $x^3-4x^2y+xy^2+8$

Explicação passo-a-passo:

10)

a)

$(4a-7)+(-2a+9)=\\4a-7-2a+9=\\2a+2$

b)

$(13x-1)+(2x-1)=\\13x-1+2x-1=\\15x-2$

c)

$2x^2-3x-2+2x^2-5x+2=\\2x^2+2x^2-3x-5x-2+2=\\4x^2-8x$

d)

$-4y^2+5y-3+4y^2+3=\\5y$

e)

$(8y^3-6y^2+16y-1)+(-8y^3-6y^2+16y-1)=\\8y^3-6y^2+16y-1-8y^3-6y^2+16y-1=\\8y^3-8y^3+16y+16y-1-1=\\32y-2$

f)

$(4y-2)-(2y+3)+(-2y+4)=\\4y-2-2y-3-2y+4=\\4y-2y-2y-2-3+4=\\4y-4y-5+4=\\-1$

g)

$(b^2-3b+2)-(-b^2+3b-2)-(2b^2-4b+1)=\\b^2-3b+2+b^2-3b+2+2b^2+4b-1=\\b^2+b^2+2b^2-3b-3b+4b+2+2-1=\\4b^2-2b-3$

h)

$(4x-2)-(3x^2+7x-2)+(-x^2+1)=\\4x-2-3x^2-7x+2-x^2+1=\\-3x^2-x^2+4x-7x-2+2+1=\\-4x^2-3x+1$

i)

$(x^3-y^3)+(2x^3-4x^2y+xy^2)-(x^3-8)=\\x^3-x^3+2x^3-4x^2y+xy^2-x^3+8=\\x^3-x^3+2x^3-x^3-4x^2y+xy^2+8=\\x^3-4x^2y+xy^2+8$