Question

pode ajudar?
x².(x²-16)=0

Answer 1

E aí mano,

$x^{2} ( x^{2} -16)=0\\\\ x^{2} =0~~~~~~~~~~~~~~ x^{2} -16=0\\ x=\pm \sqrt{0}~~~~~~~~~~ x^{2} ~=16\\ x=\pm0~~~~~~~~~~~~~x=\pm \sqrt{16} \\ x=0~~~~~~~~~~~~~~~~x=\pm4\\\\ \boxed{S=\{0,0,4,-4\}}$

Espero ter ajudado e tenha ótimos estudos =))

Answer 2

$x^2.(x^2-16)=0 \\ \\ x^2=0 \\ x= = +- \sqrt{0} \\ X=0 \\ \\ x^2=16 \\ x=+- \sqrt{16} \\ X=+-4=[ 4,-4] \\ \\ \\ S= [0,0,4,-4]$