Question

pls question ka answer bata do
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Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's solve ~

Here we can observe that Line BD is parallel to line AC.

so,

$\qquad \tt \dashrightarrow \: \angle z = 30 \degree$

[ by Alternate interior angles ]

$\qquad \tt \dashrightarrow \: \angle x = \angle A = 50 \degree$

[ opposite angles of a Parallelogram ]

$\qquad \tt \dashrightarrow \: \angle x + \angle y + 30 \degree = 180 \degree$

[ by Angle sum property of Triangle ]

$\qquad \tt \dashrightarrow \: 50 + \angle y + 30 \degree = 180 \degree$

$\qquad \tt \dashrightarrow \: \angle y + 80 \degree = 180 \degree$

$\qquad \tt \dashrightarrow \: \angle y = 180 - 80$

$\qquad \tt \dashrightarrow \: \angle y = 100 \degree$