Question

pleaseee
$15x {}^{2} + 23x - 28 = 0$
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Answer 1

Bom Dia!

15x² + 23x - 28 = 0

a: 15

b: 23

c: -28

Δ = b² - 4.a.c  

Δ = 23² - 4 . 15 . -28  

Δ = 529 = 1680

Δ = 2209

Há 2 raízes reais.

x = (-b +- √Δ)/2a

x' = (-23 + √2209)/2.15  

x' = (-23 + 47)/30

x' = 24 / 30    

x' = 4/5 ou 0,8

x'' = (-23 - √2209)/2.15  

x'' = (-23 - 47)/30    

x'' = -70 / 30

x'' = -7/3 ou -2,333...

Espero ter ajudado!

Answer 2

15x²+23x-28=0

Δ=b²-4ac

Δ=23²-4.15.(-28)

Δ=529+1680

Δ=2209

x=(-b±✓Δ)/2a

x=(-23±✓2209)2.15

x=(-23±47)/30

x1=(-23+47)/30

x1=24/30=12/15=4/5

x2=(-23-47)/30

x2=-70/30

S={4/5, -70/30}