Question

PITÁGORAS

${a}^{2} = {b}^{2} + {c}^{2}$
$a = x + 5$
$b = x + 3$
$c = 6$
${(x + 5)}^{2} = {(x + 3)}^{2} + {6}^{2}$
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Answer 1

(x+5)² = (x+3)² + (6)²

x²+10x+25 = x²+6x+9 + 36

10x -6x = 45 -25

4x = 20

x = 5

a=x+5= 10 ✓

b=x+3= 8. ✓

c= 6 ✓