Question

pfvr vcs poderiam me ajudar a armar essas equações:

1) x-4=13

2)-2x+10=0

3)-4+6x=6

4)3x-2=x+5

5)3x-2=x+5

6)3(x-2)=(x+4)

7)-3(2x-5)+2= -5(x+1)​

Answer 1

Resposta:

1) x-4=13

x = 13+4

x = 17

2)-2x+10=0

-2x = -10 .(-1)

2x = 10

x = 10/2

x = 5

3)-4+6x=6

6x = 6+4

6x = 10

x = 10/6

x = 5/3

4)3x-2=x+5

3x - x = 5+2

2x = 7

x = 7/2

5)3x-2=x+5

3x -x = 5+2

2x = 7

x = 7/2

6)3(x-2)=(x+4)

3x - 6 = x + 4

3x - x = 4+6

2x = 10

x = 10/2

x = 5

7)-3(2x-5)+2= -5(x+1)

-6x+15 +2 = -5x -5

-6x + 5x = -5 -2 -15

-x = -22 .(-1)

x = 22