Question

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Answer 1

Resposta:

Explicação passo a passo:

$7)$

  $3A=3 \times\:\left(\begin{array}{ccc}1&-1&2\\0&3&4\\\end{array}\right) =\:\left(\begin{array}{ccc}3&-3&6\\0&9&12\\\end{array}\right)$

 $4B=4 \times\:\left(\begin{array}{ccc}4&0&-3\\-1&-2&3\\\end{array}\right) =\:\left(\begin{array}{ccc}16&0&-12\\-4&-8&12\\\end{array}\right)$

 $Portanto...$

  $3A+4B=$

 $\:\left(\begin{array}{ccc}3&-3&6\\0&9&12\\\end{array}\right)+\:\left(\begin{array}{ccc}16&0&-12\\-4&-8&12\\\end{array}\right)=\left(\begin{array}{ccc}19&-3&-6\\-4&1&24\\\end{array}\right)$

              $Resposta:(B)$

$8)$

    $\left|\begin{array}{ccc}2&3\\4&8\\\end{array}\right|=2 \times8-3 \times4=16-12=4$

          $Resposta:(d)$

          $Feliz\;Ano\;Novo!$