Question

PFV ME AJUDEM NAO ESCREVAM QUALQUER COISA AE SO PRA GANHAR PONTOS ME AJUDEMMMMM PFV
1Calcule o conjunto solucao de cada equação:

Answer 1

Explicação passo-a-passo:

a)

$\frac{ {11}^{2} }{10} - \frac{3x}{5} = \frac{x}{2} \\ \\ \frac{ 121 }{10} - \frac{3x}{5} = \frac{x}{2} \\ \\ \frac{ 121 }{10} = \frac{3x}{5} + \frac{x}{2} \\ \\ 121 = 6x + 5x \\ \\ 11x = 121 \\ \\ x = \frac{121}{11} \\ \\ x = 11$

b)

$\mathsf{\frac{3}{x-5}+\frac{1}{x+5}=\frac{10-{x}^{2}}{{x}^{2}-25}}$

$\mathsf{\frac{3(x+5)+(x-5)=10-{x}^{2}}{{x}^{2}-25}}$

$\mathsf{\frac{3x+15+x-5=10-{x}^{2}}{{x}^{2}-25}}$

$\mathsf{\frac{4x+10=10-{x}^{2}}{{x}^{2}-25}}$

$\mathsf{\frac{{x}^{2}+4x}{{x}^{2}-25}=0}$

$\mathsf{{x}^{2}+4x=0}$

$\mathsf{x(x-4)=0}$

$\mathsf{x=0}$

e

$\mathsf{x-4=0}$

$\mathsf{x=4}$

S={0,4}

Answer 2

Oie, Td Bom?!

a)

$\frac{11 {}^{3} }{10} - \frac{3x}{5} = \frac{x}{2} \\ \\ \frac{1331}{10} - \frac{3x}{5} = \frac{x}{2} \\ \\ 1331 - 6x = 5x \\ \\ - 6x - 5x = - 1331 \\ \\ - 11x = - 1331 \\ \\ x = \frac{ - 1331}{ - 11} \\ \\ x = 121$

S = $\left \{121 \right \}$

b)

$\frac{3}{x - 5} + \frac{1}{x + 5} = \frac{10 - x {}^{2} }{x {}^{2} - 25} \\ \\ \frac{3}{x - 5} + \frac{1}{x + 5} - \frac{10 - x {}^{2} }{x {}^{2} - 25} = 0 \\ \\ \frac{3}{x - 5} + \frac{1}{x + 5} - \frac{10 - x {}^{2} }{(x - 5) \: . \: (x + 5)} = 0 \\ \\ \frac{3(x + 5) + x - 5 - (10 - x {}^{2}) }{(x - 5) \: . \: (x + 5)} = 0 \\ \\ \frac{3x + 15 + x - 5 - 10 + x {}^{2} }{(x - 5) \: . \: (x + 5)} = 0 \\ \\ \frac{4x + 0 + x {}^{2} }{(x - 5) \: . \: (x + 5)} = 0 \\ \\ \frac{4x + x {}^{2} }{(x - 5) \: . \: (x + 5)} = 0 \\ \\ 4x + x {}^{2} = 0 \\ \\ x \: . \: (4 + x) = 0 \\ \\ x = 0 \\ 4 + x = 0⟶x = - 4$

S = $\left \{ x_{1} = - 4 \: , \: x_{2} = 0 \right \}$

Att. Makaveli1996