Question

PFV help me!!
Determine o segundo termo do desenvolvimento de (x+3)^5 pelo binômino de Newton.

Answer 1

$Dados \to \left\{\begin{array}{ccc}(x+a)^n = (x+3)^5;\ a=3\ n=5\\\\T_{p+1} = \left(\begin{array}{ccc}n\\p\end{array}\right)*x^{n-p}*a^p \ ;\ p=1 \end{array}\right$

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}T_{1+1} = \left(\begin{array}{ccc}5\\1\end{array}\right)*x^{5-1}*3^{1} \\\\T_2 = \frac{5!}{1!*(5-1)!}*x^{4}*3\\\\ T_2 = \frac{5!}{4!}*x^4*3\\\\T_2 = 5*x^4*3\\\\\boxed{\boxed{T_2 = 15x^4}}\end{array}\right$

Espero ter ajudado. =^.^=