Question

PFV ALGUEM ME AJUDA
Determine a área de um trapézio cuja medidas são 9√3 cm, 6√3 cm e altura 2√3 cm .

Answer 1

Caso tenha problemas para visualizar a resposta experimente abrir pelo navegador https://brainly.com.br/tarefa/32708284

$\Large\boxed{\sf{\underline{\acute{A}rea~do~trap\acute{e}zio}}}\\\Huge\boxed{\boxed{\boxed{\boxed{\tt{A=\dfrac{(B+b)\cdot h}{2}}}}}}$

$\bf{Dados:}\\\rm{B=9\sqrt{3}~cm}\\\rm{b=6\sqrt{3}~cm}\\\rm{h=2\sqrt{3}~cm}\\\tt{\underline{soluc_{\!\!,}\tilde{a}o:}}\\\sf{A=\dfrac{(9\sqrt{3}+6\sqrt{3})\cdot\diagup\!\!\!2\sqrt{3}}{\diagup\!\!\!2}}\\\sf{A=15\sqrt{3}\cdot\sqrt{3}}\\\sf{A=15\diagup\!\!\!\sqrt{3^{\diagup\!\!3}}}\\\sf{A=15\cdot3}\\\huge\boxed{\boxed{\boxed{\boxed{\tt{A=45~cm^2}}}}}$

Answer 2

Explicação passo-a-passo:

$\sf S=\dfrac{(B+b)\cdot h}{2}$

$\sf S=\dfrac{(9\sqrt{3}+6\sqrt{3})\cdot2\sqrt{3}}{2}$

$\sf S=\dfrac{15\sqrt{3}\cdot2\sqrt{3}}{2}$

$\sf S=\dfrac{30\cdot3}{2}$

$\sf S=\dfrac{90}{2}$

$\sf \red{S=45~cm^2}$