Question

Pessoal me ajudem a resolver a expressão numérica conforme a foto em anexo:

Answer 1

$8\cdot5-3\cdot\{27^{\frac{1}{3}}\div\dfrac{1}{2}\cdot[1^5\cdot(2^{2^{2}}\div8+4)\div12]+25^{\frac{1}{2}}\}-2+(\sqrt{64}-6\div2)$

Os parêntesis:

$(2^{2^{2}}\div8+4)=2^4\div8+4=16\div8+4=2+4=6$

$(\sqrt{64}-6\div2)=8-3=5$

Colchetes:

$[1^5\cdot(2^{2^2}}\div8+4)\div12]=1^5\cdot6\div12=6\div12=0,5$

Observe que:

$27^{\frac{1}{3}}=\sqrt[3]{27}=3$

$25^{\frac{1}{2}}=\sqrt[2]{25}=5$

Então:

$8\cdot5-3\cdot\{27^{\frac{1}{3}}\div\dfrac{1}{2}\cdot[1^5\cdot(2^{2^{2}}\div8+4)\div12]+25^{\frac{1}{2}}\}-2+(\sqrt{64}-6\div2)=40-3\cdot\{3\div\dfrac{1}{2}\cdot0,5+5\}-2+5$

$=40-3\cdot\8-2+5=40-24-2+5=19$.