pelo processo de decomposição de fatores primos resolva o mmc dos números abaixo. a) 18 e 20.
b) 35,70 e 100
c)12,15 e 18
d)7,49,81
e)5,20 E 100
f)5,10 E 20
g)15,20 E 30
h)25,30 E 40
i) 50,65 E 200
j)49,81 e 100
Soluções para a tarefa
a)
18 20 | 2
9 10 | 2
9 5 | 3
3 5 | 3
1 5 | 5
1 1 | 5
b)
35 70 100 |2
35 35 50 | 2
35 35 25 | 5
7 7 5 | 5
7 7 1 | 7
1 1 1
c)
12 15 18 | 2
6 15 9 | 2
3 15 9 | 3
1 5 3 | 3
1 5 1 |5
1 1 1
d)
7 49 81 | 3
7 49 27 | 3
7 49 9 | 3
7 49 3 | 3
7 49 1 | 7
1 7 1 | 7
1 1 1
e)
5 20 100 | 2
5 10 50 | 2
5 5 25 | 5
1 1 5 | 5
1 1 1
f)
5 100 20 | 2
5 50 10 | 2
5 25 5 | 5
1 5 1 | 5
1 1 1
g)
15 20 30 | 2
15 10 15 | 2
15 5 15 | 3
5 5 5 | 5
1 1 1
h)
25 30 40 | 2
25 15 20 | 2
25 15 10 | 2
25 15 5 | 3
25 5 5 | 5
5 1 1 | 5
1 1 1
i)
50 65 200 | 2
25 65 100 | 2
25 65 50 | 2
25 65 25 |5
j)
49 81 100 | 2
49 81 50 | 2
49 81 25 | 3
49 27 25 | 3
49 9 25 | 3
49 3 25 | 3
49 1 25 | 5
49 1 5 | 5
49 1 1 | 7
7 1 1 | 7
1 1 1
Espero ter ajudado!
Oi...
MMC são fatores comuns e não comuns de maiores expoentes.
a)MMC (18,20)
18,20/2
9,10/2
9,5/3
3,5/3
1,5/5
1,1
MMC=2.2.3.3.5=180
b)MMC (35,70,100)
35,70,100/2
35,35,50/2
35,35,25/5
7,7,5/5
7,7,1/7
1,1,1
MMC=2.2.5.5.7=700
c) MMC (12,15,18)
12,15,18/2
6,15,9/2
3,15,9/3
1,5,3/3
1,5,1/5
1,1,1
MMC=2.2.3.3.5=180
d) MMC (7,49,81)
7,49,81/3
7,49,27/3
7,49,9/3
7,49,3/3
7,49,1/7
1,7,1/7
1,1,1
MMC = 3.3.3.3.7.7=3.969
e) MMC (5,20,100)
5,20,100/2
5,10,50/2
5,5,25/5
1,1,5/5
1,1,1
MMC= 2.2.5.5=100
f) MMC (5,10,20)
5,10,20/2
5,5,10/2
5,5,5/5
1,1,1
MMC=2.2.5=20
gMMC (15,20,30)
15,20,30/2
15,10,15/2
15,5,15/3
5,5,5/5
1,1,1
MMC=2.2.3.5=60
h) MMC (25,30,40)
25,30,40/2
25,15,20/2
25,15,10/2
25,15,5/3
25,5,5/5
5,1,1/5
1,1,1
MMC=2.2.2.3.5.5=600
i) MMC (50,65,200)
50,65,200/2
25,65,100/2
25,65,50/2
25,65,25/5
5,13,5/5
1,13,1/13
1,1,1
MMC=2.2.2.5.5.13=2.600
j) MMC (49,81,100)
49,81,100/2
49,81,50/2
49,81,25/3
49,27,25/3
49,9,25/3
49,3,25/3
49,1,25/5
49,1,5/5
49,1,1/7
7,1,1/7
1,1,1
MMC=2.2.3.3.3.5.5.7.7=396.900
Espero ter ajudado.