Question

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Answer 1

Resposta:

$a)\\ \\\frac{-4a^{4}b^{3}+2ab^{5}+7a^{2}b}{ab}=\frac{ab.(-4a^{3}b^{2}+b^{4}+7a)}{ab}=-4a^{3}b^{2}+b^{4}+7a\\ \\b)\\ \\\frac{3ax^{4}-3ax}{3axy}=\frac{3ax.(x^{3}-1)}{3ax}=x^{3}-1\\ \\c)\\\\(x-y).(3+y)=3x+xy-3y-y^{2}\\ \\c)\\ \\(2a-5).(a-2)=2a^{2}-4a+10$