Matemática, perguntado por brackzin99, 6 meses atrás

passo a passo por favor

Anexos:

Soluções para a tarefa

Respondido por remeter238
0

Resposta:

a) +(8)²= 8.8= 64

b) (-8)²= -8.-8= 64

c) (+8)³= 8.8.8= 512

d) (-8)³ = 8.8.8= -512

e) (-1)⁸ = -1.-1.-1.-1.-1.-1.-1.-1= 1

f) (-100)⁰= 1

g) (-100)¹= -100

h) (+1)¹⁰¹= 1

i) (-1)¹⁰¹ = -1

j) (+1)¹⁰⁰ = 1

k) (-1)¹⁰⁰=1

L) (-10)⁶= -10.-10.-10.-10.-10.-10= 1,000,000

Respondido por KristalGianeeC1311
0

                     Leis dos Expoentes

Vamos lembrar o seguinte:

(-a)^{n} =\boxed{\bf{a^{n}}}\ \to \texttt{se "n" e par}\\\\\\(-a)^{n} =\boxed{\bf{-a^{n}}}\ \to \texttt{se "n" e impar}\\

(+a)^{n} =\boxed{\bf{a^{n} }}

(1)^{n} =\boxed{\bf{1}}

n^{0} =\boxed{\bold{1}}

Considerando isso, resolvemos os problemas:

(+8)^{2} =8^{2} =\boxed{\bold{64}}\\\\\\(-8)^{2} =8^{2} =\boxed{\bold{64}}\\\\\\(+8)^{3} =8^{3} =\boxed{\bold{512}}\\\\\\(-8)^{3} =-8^{3} =\boxed{\bold{-512}}\\\\\\(-1)^{8} =1^{8} =\boxed{\bold{1}}\\\\\\(-100)^{0} =8^{2} =\boxed{\bf{1}}\\\\\\(-100)^{1} =\boxed{\bold{-100}}\\\\\\(+1)^{101} =1^{101} =\boxed{\bold{1}}\\\\\\

(-1)^{101} =-1^{101} =\boxed{\bold{-1}}\\\\\\(+1)^{100} =1^{100} =\boxed{\bold{1}}\\\\\\(-1)^{100} =-1^{100} =\boxed{\bold{-1}}\\\\\\(-10)^{6} =-10^{6} =\boxed{\bold{1000000}}

ESPERO TER AJUDADO, MUITO SORTE!!

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