Passe para a escala celtas cada uma das temperaturas Fahrenheit 50 graus f
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Basta fazer o seguinte :
![\dfrac{TC}{5} =\dfrac{TF - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{50 - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{18}{9} \\\\\\ 9TC = 18\cdot5 \\\\\\ 9TC = 90 \\\\\\ TC =\dfrac{90}{9} \\\\\\ TC = 10 \dfrac{TC}{5} =\dfrac{TF - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{50 - 32}{9} \\\\\\ \dfrac{TC}{5} =\dfrac{18}{9} \\\\\\ 9TC = 18\cdot5 \\\\\\ 9TC = 90 \\\\\\ TC =\dfrac{90}{9} \\\\\\ TC = 10](https://tex.z-dn.net/?f=%5Cdfrac%7BTC%7D%7B5%7D+%3D%5Cdfrac%7BTF+-+32%7D%7B9%7D+%5C%5C%5C%5C%5C%5C+%5Cdfrac%7BTC%7D%7B5%7D+%3D%5Cdfrac%7B50+-+32%7D%7B9%7D+%5C%5C%5C%5C%5C%5C+%5Cdfrac%7BTC%7D%7B5%7D+%3D%5Cdfrac%7B18%7D%7B9%7D+%5C%5C%5C%5C%5C%5C+9TC+%3D+18%5Ccdot5+%5C%5C%5C%5C%5C%5C+9TC+%3D+90+%5C%5C%5C%5C%5C%5C+TC+%3D%5Cdfrac%7B90%7D%7B9%7D+%5C%5C%5C%5C%5C%5C+TC+%3D+10)
Resposta ;
10 Celsius.
Resposta ;
10 Celsius.
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