Question

Para a≠-3 e a≠3, a expressão (a^2+6a+9)/3:(a^2-9)/(a-3) é equivalente a:

a) (a+3)/3

b)a+2

c)a+3

d)a-3

e) (a-3)/3

Answer 1

$\frac{a^{2}+6a+9}{3} ~.~\frac{(a-3)}{(a^{2}-9)} \\ \\ a^{2} +6a+9=(a+3)^{2} =(a+3)(a+3)\\ \\ (a^{2} -9)=(a+3)(a-3)\\ \\ \\ \frac{(a+3)(a+3)}{3}~.~\frac{(a-3)}{(a+3)(a-3)}~~~~~~~~simplifique \\ \\ \frac{(a+3)(a+3)}{3}~.~\frac{1}{(a+3)}~~~~~~~simplifique\\ \\ \frac{(a+3)}{3}$

Resposta: alternativa (a)

$\frac{(a+3)}{3}$