Question

para a=2, b= -10 e c= 12
$- b \: + \sqrt{ {b}^{2} - 4ac} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2a$
para a=2, b= -10 e c= 12
$- b \: - \sqrt{ {b}^{2} - 4ac } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2a$

POR FAVOR, EU PRECISO MTO

​

Answer 1

$\large\boxed{\boxed{\boxed{{Ol\'a}}}}}$

para a = +2 ; b = —10 e c = +12

$Então:$

$\LARGE{\Delta=(-10)^2-4×2×12}$

$\LARGE{\Delta=+100-96}$

$\LARGE{\Delta=4}$

$\LARGE{X_{1},_{2}=\frac{-b±\sqrt{\Delta}}{2.a}}$

$\LARGE{X_{1}=\frac{-(-10)+\sqrt{4}}{2.2}}$

$\LARGE{X_{1}=\frac{+10+2}{+4}}$

$\LARGE{X_{1}=\frac{+12}{+4}}$

$\LARGE{\large\boxed{{X_{1}=+3}}}}}}$\:\:$\checkmark{\checkmark}$

$\LARGE{X_{2}=\frac{-(-10)-2}{2.2}}$

$\LARGE{X_{2}=\frac{+10-2}{+4}}$

$\LARGE{X_{2}=\frac{+8}{+4}}$

${LARGE{\large\boxed{{X_{2}=2}}}}}}$