Question

p(x)=(a-b+1)x2+(b-2c)x+(2c-1)

Answer 1

P(x)=(a-b+1)x2+(b-2c)x+(2c-1)
        
(a - b +1) x² + ( b - 2c)x + (2c - 1)

(ax² - bx² + 1x²) + (bx - 2cx) + (2c - 1)

ax² - bx² + x² + bx - 2cx + 2c - c 

P(x) = ax² - bx² + x² + bx - 2cx + 2c - c