Question

p(x) = 2x³-kx²+3x-2k, para que valores de K temos p(2)=4?

Answer 1

Ola Lucas

P(x) = 2x³ - kx² + 3x - 2k 

P(2) = 16 - 4k + 6 - 2k = 4

6k = 16 + 6 - 4 = 18 

k = 3 

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Answer 2

$p(x) = 2x {}^{3} - kx {}^{2} + 3x - 2k \\ \boxed{p(2) = 4} \\ 4 = 2 \: . \: 2 {}^{3 } - k \: . \: 2 {}^{2} + 3 \: . \: 2 - 2k \\ 4 = 2 \: . \: 8 - k \: . \: 4 + 3 \: . \: 2 - 2k \\ 4 = 16 - 4k + 6 - 2k \\ 4 = 22 - 6k \\ 6k = 22 - 4 \\ 6k = 18 \\ k = \frac{18}{6} \\ \boxed{\boxed{\boxed{k = 3}}}$

atte. yrz