Question

Os zeros ou raizes da função y= 3x²+x -2

Answer 1

$y=3x^2+x-2$

$3x^2+x-2=0$

$\Delta=1^2-4\cdot3\cdot(-2)$
$\Delta=1+24$
$\Delta=25$

$x=\dfrac{-1\pm\sqrt{25}}{2\cdot3}=\dfrac{-1\pm5}{6}$

$x'=\dfrac{-1+5}{6}~\longrightarrow~x'=\dfrac{4}{6}~\longrightarrow~\boxed{x'=\dfrac{2}{3}}$


$x"=\dfrac{-1-5}{6}~\longrightarrow~x"=\dfrac{-6}{6}~\longrightarrow~\boxed{x"-1}$