Question

Os 4 primeiro termo de an=2n+3 e an=6n. 2n+2?

Answer 1

an=2n+3

a1= 2(1) + 3 = 2+3 = 5
a2= 2(2) + 3 = 4+3 = 7
a3= 2(3) + 3 = 6+3 = 9
a4= 2(4) + 3 = 8+3 = 11

( 5,7,9,11,...)
=======================================
an=6n. 2n+2


a1=6.1.[ 2(.1)+2)] = 6.[2+2] = 6.4 = 24
a2=6.2.[ 2(.2)+2)] = 12.[4+2] = 12.6 = 72
a3=6.3.[ 2(.3)+2)] = 18[6+2] = 18.8 = 144
a4=6.4.[ 2(.4)+2)] = 24.[8+2] = 24.10 = 240

( 24,72,144,240,..)