Question

organize e reponda formula delta e bhaskara 4x²-x+1=x+3x²

Answer 1

$4 x^{2} -x+1=x+3 x^{2}\to \\\\4 x^{2} -3 x^{2} -x-x-1=0\to\\\\ x^{2} -2x-1=0\\ a=1;b=-2;c=-1\\\\\\ \Delta=b^2-4ac\to\\ \Delta=(-2)^2-4*1*(-1)\to\\ \Delta=4+4\to\\ \Delta=8\\\\ x' \neq x''\\\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-(-2)\pm \sqrt{8} }{2*1} \to x= \frac{2\pm 2 \sqrt{2} }{2} \to \\\\\\ x'= \frac{2+2 \sqrt{2} }{2} \to x'= 1+ \sqrt{2}\\\\\\x''= \frac{2-2 \sqrt{2} }{2} \to x''= 1- \sqrt{2}\\\\\\\\ S=( 1- \sqrt{2}; 1+ \sqrt{2})$

Answer 2

4x* - 3x* -x -x +1 = 0
1x* - 2x + 1 = 0 [ a=1
b= -2
c = 1
fórmula de bhaskara: - b ± raiz de delta
—————————
2a
delta: b* - 4ac
Logo:
2* -4.1.1 = 0
4-4=0
DELTA =0.
-1
—— = -1/2(RESPOSTA)
2.1