Question

OPERANDO COM NOTAÇÃO CIENTÍFICA

Adição e Subtração com notação científica podem me ajudar preciso até segunda feira pfv​

Answer 1

Explicação passo-a-passo:

1.

a) $2,9\cdot10^3+4,23\cdot10^3=(2,9+4,23)\cdot10^3$

$2,9\cdot10^3+4,23\cdot10^3=7,13\cdot10^3$

b) $32,26\cdot10^2+5,42\cdot10^2=(32,26+5,42)\cdot10^2$

$32,26\cdot10^2+5,42\cdot10^2=37,68\cdot10^2$

$32,26\cdot10^2+5,42\cdot10^2=3,768\cdot10^3$

c) $36,478\cdot10^8-5,362\cdot10^8=(36,478-5,362)\cdot10^8$

$36,478\cdot10^8-5,362\cdot10^8=31,116\cdot10^8$

$36,478\cdot10^8-5,362\cdot10^8=3,1116\cdot10^9$

d) $42,32\cdot10^5-6,21\cdot10^5=(42,32-6,21)\cdot10^5$

$42,32\cdot10^5-6,21\cdot10^5=36,11\cdot10^5$

$42,32\cdot10^5-6,21\cdot10^5=3,611\cdot10^6$

2.

a) $2,3\cdot10^2\times2,2\cdot10^4=(2,3\times2,2)\cdot(10^2\times10^4)$

$2,3\cdot10^2\times2,2\cdot10^4=5,06\cdot10^6$

b) $1,3\cdot10^2\times2,1\cdot10^3=(1,3\times2,1)\cdot(10^2\times10^3)$

$1,3\cdot10^2\times2,1\cdot10^3=2,73\cdot10^5$

c) $2,1\cdot10^{12}\div8,5\cdot10^9=(2,1\div8,5)\cdot(10^{12}\div10^9)$

$2,1\cdot10^{12}\div8,5\cdot10^9=0,247\cdot10^3$

$2,1\cdot10^{12}\div8,5\cdot10^9=2,47\cdot10^2$

d) $9,5\cdot10^8\div2,5\cdot10^6=(9,5\div2,5)\cdot(10^8\div10^6)$

$9,5\cdot10^8\div2,5\cdot10^6=3,8\cdot10^2$