Question

Operações com radicais
efetue as adiçoes e subtrações porfavor e pra hoje​

Answer 1

a)

$\sqrt{7} + \sqrt{7} + \sqrt{7} = 3 \sqrt{7}$

b)

$5 \sqrt{2} - 3 \sqrt{2} + 2 \sqrt{2} = 4 \sqrt{2}$

c)

$8 \sqrt{3} - 2 \sqrt{3} - 8 \sqrt{3} + \sqrt{3} = - \sqrt{3}$

d)

$\sqrt{3} + \sqrt{27} \\ \sqrt{3} + \sqrt{9 \times 3} \\ \sqrt{3} + ( \sqrt{9} \times \sqrt{3} ) \\ \sqrt{3} + 3 \sqrt{3} \\ 4 \sqrt{3}$

e)

$7 \sqrt{2} + \sqrt{50} \\ 7 \sqrt{2} + \sqrt{25 \times 2} \\ 7 \sqrt{2} + ( \sqrt{25} \times \sqrt{2} ) \\ 7 \sqrt{2} + 5 \sqrt{2} \\ 12 \sqrt{2}$

f)

$\sqrt{12} - \sqrt{72} + \sqrt{3} \\ \sqrt{3 \times 4} - \sqrt{3 \times 24} + \sqrt{3} \\( \sqrt{3} \times \sqrt{4} ) - ( \sqrt{3} \times \sqrt{24} ) + \sqrt{3} \\ \sqrt{3} ( \sqrt{4} - \sqrt{24} + 1) \\ \sqrt{3} (2 - \sqrt{4 \times 6} + 1) \\ \sqrt{3} (2 - \sqrt{4} \times \sqrt{6} + 1) \\ \sqrt{3} (2 - 2 \sqrt{6} + 1) \\ \sqrt{3} (3 - 2 \sqrt{6} )$