Question

Operações com notações científicas. me ajudem pfvrrr

Answer 1

Resposta:

Explicação passo-a-passo:

1)

Cel/ hab

= 52000000/40000000

= 52/40 (:4)/(:4)

= 13/10

= 1,3

2)

Cel/hab

= 20000000/16000000

= 20/16 (:4)/(:4)

= 5/4

= 1,25

3) R.: d

= 0,000015.0,000000002

= 15.10^(-6).2.10^(-9)

= 30.10^(-6).(-9)

= 3.10.10^(-15)

= 3.10^(-14)

4)

A)

= 3,5.10^4 . 2,7.10^3

= 35.10^(-1).10^4. 27.10^(-1).10^3

= 35.10^3. 27.10^2

= 35.27.10^5

= 945.10^5

= 9,45.10^2.10^5

= 9,45.10^7

B)

3,7.10^5 . 2,1.10^8

= 3,7. 2,1 . 10^13

= 7,77 . 10^13

C)

5,2.10^5 . 4,2.10^(-2)

= 5,2.4,2. 10^3

= 52/42 (:2)/(;2) . 10^3

= 26/21 . 10^3

= 1,238.10^3

D)

6,2.10^8 / 2,1.10^3

6,2/2,1 . 10^(8-3)

62/21 . 10^5

R.: = 2,95.10^5

E)

7,5.10^3 / 3,5.10^6

75.35 (:5)/(:5). 10^(3-6)

15/7 . 10^(-3)

R.: = 2,14.10^(-3)

F)

3,75.10^4 / 3.10^(-2)

3,75/3 . 10^4 . 10^2

R.: = 1,25.10^6